What is the derivative of (3x^2-2x+3^5) ?

The derivative of (3x^2-2x+3^5) is 5(3x^2-2x+3)^4(6x-2)

What is the first derivative of (3x^2-2x+3^5) ?

The first derivative of (3x^2-2x+3^5) is 5(3x^2-2x+3)^4(6x-2)

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\frac{d}{d x} ((3 x^{2} - 2 x + 3)^{5})

5 (3 x^{2} - 2 x + 3)^{4} (6 x - 2)

Solution steps

\frac{d}{d x} ((3 x^{2} - 2 x + 3)^{5})

Apply the chain rule:

5 (3 x^{2} - 2 x + 3)^{4} \frac{d}{d x} (3 x^{2} - 2 x + 3)

= 5 (3 x^{2} - 2 x + 3)^{4} \frac{d}{d x} (3 x^{2} - 2 x + 3)

\frac{d}{d x} (3 x^{2} - 2 x + 3) = 6 x - 2

= 5 (3 x^{2} - 2 x + 3)^{4} (6 x - 2)

f (x) = ln (2 x + 1)

x^{2} d y + (2 x y - x + 1) d x = 0

\int 3 cos (x) - \frac{1}{x ^{3}} d x

\frac{d}{d x} (m (x - s) e^{k (x - d)} + p (x, d))

x \to \infty lim (3 x^{2} + 2)

What is the derivative of (3x^2-2x+3^5) ?
The derivative of (3x^2-2x+3^5) is 5(3x^2-2x+3)^4(6x-2)
What is the first derivative of (3x^2-2x+3^5) ?
The first derivative of (3x^2-2x+3^5) is 5(3x^2-2x+3)^4(6x-2)