What is the solution for y^{''}+6y^'+9y=0,y(0)=5,y^'(0)=9 ?

The solution for y^{''}+6y^'+9y=0,y(0)=5,y^'(0)=9 is y=5e^{-3t}+24te^{-3t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+6y^'+9y=0,y(0)=5,y^'(0)=9

y^{^{''}} + 6 y^{^{'}} + 9 y = 0, y (0) = 5, y^{^{'}} (0) = 9

y = 5 e^{- 3 t} + 24 t e^{- 3 t}

Solution steps

y^{''} (t) + 6 y^{'} (t) + 9 y = 0

Solve linear ODE:

y = 5 e^{- 3 t} + 24 t e^{- 3 t}

y = 5 e^{- 3 t} + 24 t e^{- 3 t}

6 y^{^{''}} - 7 y^{^{'}} + y = 0

y^{^{'''}} - 17 y^{^{''}} + 40 y^{^{'}} + 300 y = 0

y^{^{''}} + 4 y^{^{'}} = 0, y (0) = 1, y^{^{'}} (0) = - 1

\frac{24}{32} y^{^{''}} + 72 y = 0

y^{^{''}} + 2 y^{^{'}} + y = 0, y^{1} = x e^{- x}

What is the solution for y^{''}+6y^'+9y=0,y(0)=5,y^'(0)=9 ?
The solution for y^{''}+6y^'+9y=0,y(0)=5,y^'(0)=9 is y=5e^{-3t}+24te^{-3t}