What is the integral from-3 to-3 of 6 ?

The integral from-3 to-3 of 6 is 0

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integral from-3 to-3 of 6

\int_{- 3}^{- 3} 6 d x

0

Solution steps

\int_{- 3}^{- 3} 6 d x

Integral of a constant:

\int a d x = a x

= [6 x]_{- 3}^{- 3}

Compute the boundaries:

0

= 0

\frac{d}{d x} ((7 + \frac{5}{x})^{x})

y = \frac{3 ( 2 x ^{5} - 7 )}{x ^{4}}

f (x) = (x + 1)^{x}

\int_{0}^{2} 9 - x^{2} d x

g (x) = \frac{5 + 2 x}{7 - 8 x}