What is u^{''}+0.3u^'+2.7\H(t)=0 ?

The answer to u^{''}+0.3u^'+2.7\H(t)=0 is 0+0.3*0+2.7\H(t(x))=0

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u^{''}+0.3u^'+2.7\H(t)=0

u^{''} + 0.3 u^{'} + 2.7 H (t (x)) = 0

0 + 0.3 \cdot 0 + 2.7 H (t (x)) = 0

Solution steps

u^{''} + 0.3 u^{'} + 2.7 H (t (x)) = 0

u^{''} = 0

0 + 0.3 u^{^{'}} + 2.7 H (t (x)) = 0

u^{'} = 0

0 + 0.3 \cdot 0 + 2.7 H (t (x)) = 0

y^{^{''}} + 5 y^{^{'}} + y = 0, y (0) = 0

y^{^{''}} - 5 y^{^{'}} - 6 y = 0, y (0) = - 1, y^{^{'}} (0) = 15

y^{^{'''}} + 48 y^{^{''}} + 768 y^{^{'}} + 4096 y = 0

y^{^{''}} - 5 y^{^{'}} + 6 y = 0, y^{^{'}} (0) = 1

10 y^{^{''}} - 50 y^{^{'}} + 65 y = 0, y (0) = 1, y^{^{'}} (0) = 1

What is u^{''}+0.3u^'+2.7\H(t)=0 ?
The answer to u^{''}+0.3u^'+2.7\H(t)=0 is 0+0.3*0+2.7\H(t(x))=0