What is the solution for 625y^{''''}-y=0 ?

The solution for 625y^{''''}-y=0 is y=c_{1}e^{t/5}+c_{2}e^{-t/5}+c_{3}cos(t/5)+c_{4}sin(t/5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

625y^{''''}-y=0

625 y^{^{''''}} - y = 0

y = c_{1} e^{\frac{t}{5}} + c_{2} e^{- \frac{t}{5}} + c_{3} cos (\frac{t}{5}) + c_{4} sin (\frac{t}{5})

Solution steps

625 y^{(4)} (t) - y = 0

Solve linear ODE:

y = c_{1} e^{\frac{t}{5}} + c_{2} e^{- \frac{t}{5}} + c_{3} cos (\frac{t}{5}) + c_{4} sin (\frac{t}{5})

y = c_{1} e^{\frac{t}{5}} + c_{2} e^{- \frac{t}{5}} + c_{3} cos (\frac{t}{5}) + c_{4} sin (\frac{t}{5})

10 y^{^{''}} + 9 y^{^{'}} + 2 y^{^{'}} = 0

0.1 y^{^{''}} + y^{^{'}} + y = 0

4 y^{^{''}} + 14 y^{^{'}} - 8 y = 0

x^{^{''}} + 11 x + 20 x = 0

y^{^{''}} + 4 y^{^{'}} + cy = 0, y (0) = 0, y^{^{'}} (0) = - 3

What is the solution for 625y^{''''}-y=0 ?
The solution for 625y^{''''}-y=0 is y=c_{1}e^{t/5}+c_{2}e^{-t/5}+c_{3}cos(t/5)+c_{4}sin(t/5)