What is the derivative of (2x+1(3x-2)) ?

The derivative of (2x+1(3x-2)) is 12x-1

What is the first derivative of (2x+1(3x-2)) ?

The first derivative of (2x+1(3x-2)) is 12x-1

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\frac{d}{d x} ((2 x + 1) (3 x - 2))

12 x - 1

Solution steps

\frac{d}{d x} ((2 x + 1) (3 x - 2))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 2 x + 1, g = 3 x - 2

= \frac{d}{d x} (2 x + 1) (3 x - 2) + \frac{d}{d x} (3 x - 2) (2 x + 1)

\frac{d}{d x} (2 x + 1) = 2

\frac{d}{d x} (3 x - 2) = 3

= 2 (3 x - 2) + 3 (2 x + 1)

Simplify

2 (3 x - 2) + 3 (2 x + 1) : 12 x - 1

= 12 x - 1

\frac{\partial}{\partial x} (8 x^{3} - 24 x y + y^{3})

\int 8 sec^{3} (3 x) d x

y^{^{'}} + y \cdot cos (t) = sin (t) \cdot cos (t)

\int + \frac{x + 7}{x ^{2} + 4} d x

x^{3} (4 - x)

What is the derivative of (2x+1(3x-2)) ?
The derivative of (2x+1(3x-2)) is 12x-1
What is the first derivative of (2x+1(3x-2)) ?
The first derivative of (2x+1(3x-2)) is 12x-1