What is the solution for x^{''}+0/(1/32)x^'+(13)/(1/32)x=0 ?

The solution for x^{''}+0/(1/32)x^'+(13)/(1/32)x=0 is x=c_{1}cos(4sqrt(26)t)+c_{2}sin(4sqrt(26)t)

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x^{''}+0/(1/32)x^'+(13)/(1/32)x=0

x^{^{''}} + \frac{0}{\frac{1}{32}} x^{^{'}} + \frac{13}{\frac{1}{32}} x = 0

x = c_{1} cos (426 t) + c_{2} sin (426 t)

Solution steps

x^{''} (t) + \frac{0}{\frac{1}{32}} x^{'} (t) + \frac{13}{\frac{1}{32}} x = 0

Solve linear ODE:

x = c_{1} cos (426 t) + c_{2} sin (426 t)

x = c_{1} cos (426 t) + c_{2} sin (426 t)

y^{^{''}} + 4 y^{^{'}} + 20 y = 0, y (π) = 5, y (0) = 6

(D^{3} - 4 D^{2} + 3 D) y = 0

1.5 y^{^{''}} + 12 y^{^{'}} + 24 y = 0

y^{^{''}} - 7 y^{^{'}} + 12 y = 0, y^{0} = 0, y^{^{'}} = 3

49 y^{^{''}} + 140 y^{^{'}} + 136 y = 0, y (0) = 7, y^{^{'}} (0) = 6

What is the solution for x^{''}+0/(1/32)x^'+(13)/(1/32)x=0 ?
The solution for x^{''}+0/(1/32)x^'+(13)/(1/32)x=0 is x=c_{1}cos(4sqrt(26)t)+c_{2}sin(4sqrt(26)t)