What is the solution for y^{''}+16y=0,y(pi)=0,y(0)=0 ?

The solution for y^{''}+16y=0,y(pi)=0,y(0)=0 is y=c_{2}sin(4t)

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y^{''}+16y=0,y(pi)=0,y(0)=0

y^{^{''}} + 16 y = 0, y (π) = 0, y (0) = 0

y = c_{2} sin (4 t)

Solution steps

y^{''} (t) + 16 y = 0

Solve linear ODE:

y = c_{2} sin (4 t)

y = c_{2} sin (4 t)

y^{^{''}} + 3 y^{^{'}} = 0, y (0) = - 2, y^{^{'}} (0) = 3

y^{^{''}} + 8 y^{^{'}} + 16 y = 0, y (0) = 6, y^{^{'}} (0) = 2

y^{^{''}} + 121 y = 0, y (0) = sin (k t)

2 y^{^{''}} + 11 y^{^{'}} + 8 y = 0, y (0) = 5, y^{^{'}} (0) = 0

y^{^{''}} + y = 0, y (0) = 0, y^{^{'}} (0) = 0

What is the solution for y^{''}+16y=0,y(pi)=0,y(0)=0 ?
The solution for y^{''}+16y=0,y(pi)=0,y(0)=0 is y=c_{2}sin(4t)