What is area y=2(x+1),y=3(x+1),x=7 ?

The answer to area y=2(x+1),y=3(x+1),x=7 is 32

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area y=2(x+1),y=3(x+1),x=7

area

y = 2 (x + 1), y = 3 (x + 1), x = 7

32

Solution steps

Apply the area formula:

\int_{- 1}^{7} ∣ x + 1 ∣ d x

Solve

\int_{- 1}^{7} ∣ x + 1 ∣ d x : 32

The area is:

= 32

\frac{( t + 5 ) 2}{3 ( 2 t ^{2} - 3 ) 3}

\int 2 x - 9 d x

\frac{d y}{d r} = 2 + y - 2 r + 3

\frac{d}{d x} (sin^{3} (x) + cos^{3} (x))

What is area y=2(x+1),y=3(x+1),x=7 ?
The answer to area y=2(x+1),y=3(x+1),x=7 is 32