What is the solution for y^{''}+6y^'+5y=0,y(0)=3,y^'(0)=-44 ?

The solution for y^{''}+6y^'+5y=0,y(0)=3,y^'(0)=-44 is y=(3-41/4)e^{-t}+41/4 e^{-5t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+6y^'+5y=0,y(0)=3,y^'(0)=-44

y^{^{''}} + 6 y^{^{'}} + 5 y = 0, y (0) = 3, y^{^{'}} (0) = - 44

y = (3 - \frac{41}{4}) e^{- t} + \frac{41}{4} e^{- 5 t}

Solution steps

y^{''} (t) + 6 y^{'} (t) + 5 y = 0

Solve linear ODE:

y = (3 - \frac{41}{4}) e^{- t} + \frac{41}{4} e^{- 5 t}

y = (3 - \frac{41}{4}) e^{- t} + \frac{41}{4} e^{- 5 t}

y^{^{''}} + 7 y^{^{'}} + 16 y = 0

y^{^{''}} + α 2 y^{^{'}} + 2 y = 0

y^{^{''}} - 6 y^{^{'}} - 2 y = 0, y (0) = 1, y^{^{'}} (0) = 1

\frac{d ^{2} y}{d x ^{2}} = - 36 y

y^{^{''}} - 6 y^{^{'}} + 25 y = 0, y (0) = - 3, y^{^{'}} (0) = - 1

What is the solution for y^{''}+6y^'+5y=0,y(0)=3,y^'(0)=-44 ?
The solution for y^{''}+6y^'+5y=0,y(0)=3,y^'(0)=-44 is y=(3-41/4)e^{-t}+41/4 e^{-5t}