What is the solution for y^{''}-6y^'+9y=0,y(0)=23,y(1)=0 ?

The solution for y^{''}-6y^'+9y=0,y(0)=23,y(1)=0 is y=23e^{3t}-23e^{3t}t

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y^{''}-6y^'+9y=0,y(0)=23,y(1)=0

y^{^{''}} - 6 y^{^{'}} + 9 y = 0, y (0) = 23, y (1) = 0

y = 23 e^{3 t} - 23 e^{3 t} t

Solution steps

y^{''} (t) - 6 y^{'} (t) + 9 y = 0

Solve linear ODE:

y = 23 e^{3 t} - 23 e^{3 t} t

y = 23 e^{3 t} - 23 e^{3 t} t

y^{^{'''}} - 2 y^{^{'}} = 0

y^{^{''}} + 9 y = 0, y (0) = 4, y^{^{'}} (0) = 1

4 y^{^{''}} - 2 y^{^{'}} + y = 0

16 y^{^{''}} - 8 y^{^{'}} + 145 y = 0, y (0) = 1

16 \cdot y^{^{''}} + 24 \cdot y^{^{'}} + 73 \cdot y = 0, y (0) = [4]

What is the solution for y^{''}-6y^'+9y=0,y(0)=23,y(1)=0 ?
The solution for y^{''}-6y^'+9y=0,y(0)=23,y(1)=0 is y=23e^{3t}-23e^{3t}t