What is the integral of 6^x-sec^2(x) ?

The integral of 6^x-sec^2(x) is (6^x)/(ln(6))-tan(x)+C

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integral of 6^x-sec^2(x)

\int 6^{x} - sec^{2} (x) d x

\frac{6 ^{x}}{ln ( 6 )} - tan (x) + C

Solution steps

\int 6^{x} - sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 6^{x} d x - \int sec^{2} (x) d x

\int 6^{x} d x = \frac{6 ^{x}}{ln ( 6 )}

\int sec^{2} (x) d x = tan (x)

= \frac{6 ^{x}}{ln ( 6 )} - tan (x)

Add a constant to the solution

= \frac{6 ^{x}}{ln ( 6 )} - tan (x) + C

\int 6 x^{2} ln (x) d x

\int \frac{1}{9 x ^{2} - 4} d x

\frac{\partial}{\partial x} (y^{3} + 3 x y - x^{3})

e^{- x^{3}}

\int \frac{x}{u}

What is the integral of 6^x-sec^2(x) ?
The integral of 6^x-sec^2(x) is (6^x)/(ln(6))-tan(x)+C