What is the solution for -derivative of y=3x ?

The solution for -derivative of y=3x is y=-(3x^2)/2+c_{1}

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Find the Derivative - d/dx y=3x

- \frac{d}{d x} y = 3 x

y = - \frac{3 x ^{2}}{2} + c_{1}

Solution steps

- \frac{d y}{d x} = 3 x

Isolate

y^{'} (x) : y^{'} (x) = - 3 x

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - 3 x d x

\int - 3 x d x = - \frac{3 x ^{2}}{2} + c_{1}

y = - \frac{3 x ^{2}}{2} + c_{1}

(2, 5), (3, 6)

f = 4 x + 3

cos (θ)

- \frac{d}{d x} (cos (x))

\int (\frac{1}{( e ^{x} )}) d x

What is the solution for -derivative of y=3x ?
The solution for -derivative of y=3x is y=-(3x^2)/2+c_{1}