What is the integral of 1/((x^{-2))} ?

The integral of 1/((x^{-2))} is (x^3)/3+C

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Find the Antiderivative 1/(x^-2)

integral

\frac{1}{( x ^{- 2} )}

\frac{x ^{3}}{3} + C

Solution steps

\int \frac{1}{x ^{- 2}} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= \frac{x ^{3}}{3}

Add a constant to the solution

= \frac{x ^{3}}{3} + C

- \frac{d}{d x} (sin (2 x))

- \frac{d}{d x} (\frac{1}{( 1 + x ^{2} )})

- \frac{d}{d x} y = 5 x

(- 4, 2), (4, - 4)

- \frac{d}{d x} (sin (x^{2}))

What is the integral of 1/((x^{-2))} ?
The integral of 1/((x^{-2))} is (x^3)/3+C