What is the solution for -derivative of y=2e^x ?

The solution for -derivative of y=2e^x is y=-2e^x+c_{1}

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Find the Derivative - d/dx y=2e^x

- \frac{d}{d x} y = 2 e^{x}

y = - 2 e^{x} + c_{1}

Solution steps

- \frac{d y}{d x} = 2 e^{x}

Isolate

y^{'} (x) : y^{'} (x) = - 2 e^{x}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - 2 e^{x} d x

\int - 2 e^{x} d x = - 2 e^{x} + c_{1}

y = - 2 e^{x} + c_{1}

- \frac{d}{d x} (x cos (x))

- \frac{d}{d x} (cos (x) sec (x))

- \frac{d}{d x} (e^{3 x})

(4, 0), (0, 3)

x \to \infty lim (\frac{x}{4})

What is the solution for -derivative of y=2e^x ?
The solution for -derivative of y=2e^x is y=-2e^x+c_{1}