What is the solution for (dy)/(dx)y=2x ?

The solution for (dy)/(dx)y=2x is y=sqrt(2x^2+c_{1)},y=-sqrt(2x^2+c_{1)}

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Find dy/dx y=2x

\frac{d y}{d x} y = 2 x

y = 2 x^{2} + c_{1}, y = - 2 x^{2} + c_{1}

Solution steps

\frac{d y}{d x} y = 2 x

Solve separable ODE:

y = 2 x^{2} + c_{1}, y = - 2 x^{2} + c_{1}

y = 2 x^{2} + c_{1}, y = - 2 x^{2} + c_{1}

- \frac{d}{d x} (x^{\frac{1}{2}})

- \frac{d}{d x} y = sin (x)

f (x) = cos (2 x)

- \frac{d}{d} y - 2 y

- \frac{d}{d x} (2 x)

What is the solution for (dy)/(dx)y=2x ?
The solution for (dy)/(dx)y=2x is y=sqrt(2x^2+c_{1)},y=-sqrt(2x^2+c_{1)}