What is the solution for -derivative of f(x)=e^{4x} ?

The solution for -derivative of f(x)=e^{4x} is f(x)=-1/4 e^{4x}+c_{1}

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Find the Derivative - d/dx f(x)=e^(4x)

- \frac{d}{d x} f (x) = e^{4 x}

f (x) = - \frac{1}{4} e^{4 x} + c_{1}

Solution steps

- \frac{df}{d x} = e^{4 x}

Isolate

f^{'} (x) : f^{'} (x) = - e^{4 x}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int - e^{4 x} d x

\int - e^{4 x} d x = - \frac{1}{4} e^{4 x} + c_{1}

f (x) = - \frac{1}{4} e^{4 x} + c_{1}

- \frac{d}{d x} y = 6 x

- \frac{d}{d x} (7 x)

\frac{d y}{d x} y = tan (x)

- \frac{d}{d x} (tan^{3} (x))

cos (\frac{x}{( 2 )})

What is the solution for -derivative of f(x)=e^{4x} ?
The solution for -derivative of f(x)=e^{4x} is f(x)=-1/4 e^{4x}+c_{1}