What is the solution for -derivative of y=4x ?

The solution for -derivative of y=4x is y=-2x^2+c_{1}

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Find the Derivative - d/dx y=4x

- \frac{d}{d x} y = 4 x

y = - 2 x^{2} + c_{1}

Solution steps

- \frac{d y}{d x} = 4 x

Isolate

y^{'} (x) : y^{'} (x) = - 4 x

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - 4 x d x

\int - 4 x d x = - 2 x^{2} + c_{1}

y = - 2 x^{2} + c_{1}

- \frac{d}{d x} y = 2 x^{2}

- \frac{d}{d x} (cot (2 x))

- \frac{d}{d x} (1) - cos (x)

\frac{1}{( sin ( 2 x ) ) , x}

- \frac{d}{d x} (e^{x}) - 3

What is the solution for -derivative of y=4x ?
The solution for -derivative of y=4x is y=-2x^2+c_{1}