What is the integral of 1/((tan(x))) ?

The integral of 1/((tan(x))) is ln|sin(x)|+C

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Find the Antiderivative 1/(tan(x))

integral

\frac{1}{( tan ( x ) )}

ln ∣ sin (x) ∣ + C

Solution steps

\int \frac{1}{tan ( x )} d x

Rewrite using trig identities

= \int \frac{cos ( x )}{sin ( x )} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = sin (x)

= ln ∣ sin (x) ∣

Add a constant to the solution

= ln ∣ sin (x) ∣ + C

\frac{d}{d x} y = 8 x

2 x^{3} - 5 x, (1, - 3)

\frac{d}{d x} (tan (x) sec (x))

\frac{d}{d x} ((\frac{50}{( x )}) x)

h \to 0 lim \frac{( ( x + h ) ^{4} - x ^{4} )}{h}

What is the integral of 1/((tan(x))) ?
The integral of 1/((tan(x))) is ln|sin(x)|+C