What is the solution for -derivative of y=sqrt(sec(2x)) ?

The solution for -derivative of y=sqrt(sec(2x)) is y=integral of-sqrt(sec(2x))

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Find the Derivative - d/dx y = square root of sec(2x)

- \frac{d}{d x} y = sec (2 x)

y = \int - sec (2 x) d x

Solution steps

- \frac{d y}{d x} = sec (2 x)

Isolate

y^{'} (x) : y^{'} (x) = - sec (2 x)

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - sec (2 x) d x

y = \int - sec (2 x) d x

\int (e^{a x}) d x

(4, 6), (- 4, - 6)

- \frac{d}{d} u arcsin (u)

x \to 0 lim (\frac{( sin ( x ) )}{( ∣ x ∣ )})

- \frac{d}{d x} (arctan (\frac{y}{x}))

What is the solution for -derivative of y=sqrt(sec(2x)) ?
The solution for -derivative of y=sqrt(sec(2x)) is y=integral of-sqrt(sec(2x))