What is the solution for -derivative of y=8^x ?

The solution for -derivative of y=8^x is y=-(8^x)/(3ln(2))+c_{1}

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Find the Derivative - d/dx y=8^x

- \frac{d}{d x} y = 8^{x}

y = - \frac{8 ^{x}}{3 ln ( 2 )} + c_{1}

Solution steps

- \frac{d y}{d x} = 8^{x}

Isolate

y^{'} (x) : y^{'} (x) = - 8^{x}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - 8^{x} d x

\int - 8^{x} d x = - \frac{8 ^{x}}{3 ln ( 2 )} + c_{1}

y = - \frac{8 ^{x}}{3 ln ( 2 )} + c_{1}

- \frac{d}{d x} (tan (\frac{1}{x}))

\frac{( cos ( 2 x ) )}{2}

(- 4, 4), (4, 4)

- \frac{d}{d x} (\frac{x}{5})

e^{3 x}

What is the solution for -derivative of y=8^x ?
The solution for -derivative of y=8^x is y=-(8^x)/(3ln(2))+c_{1}