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Popular >

integral from 1 to 3 of |t-2|

Solution

\int_{1}^{3} ∣ t - 2 ∣ d t

Solution

1

Solution steps

\int_{1}^{3} ∣ t - 2 ∣ d t

Eliminate Absolutes

= \int_{1}^{2} - t + 2 d t + \int_{2}^{3} t - 2 d t

\int_{1}^{2} - t + 2 d t = \frac{1}{2}

\int_{2}^{3} t - 2 d t = \frac{1}{2}

= \frac{1}{2} + \frac{1}{2}

Simplify

\frac{1}{2} + \frac{1}{2} : 1

= 1

Popular Examples

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\int \frac{1}{x ^{2} - 5} d x

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integral of 1/((x+1)^3sqrt(x^2+2x))

\int \frac{1}{( x + 1 ) ^{3} x ^{2} + 2 x} d x

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integral of sin(2x)cos(3x)

\int sin (2 x) cos (3 x) d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 3 of |t-2| ?
The integral from 1 to 3 of |t-2| is 1