derivative of y=sin(1/x)

解答

\frac{d}{d x} y = sin (\frac{1}{x})

y = x sin (\frac{1}{x}) - Ci (\frac{1}{x}) + c_{1}

求解步骤

\frac{d y}{d x} = sin (\frac{1}{x})

若

f^{^{'}} (x) = g (x)

则

f (x) = \int g (x) d x

y = \int sin (\frac{1}{x}) d x

y = x sin (\frac{1}{x}) - Ci (\frac{1}{x}) + c_{1}

\frac{d}{d x} (\frac{( sin ( x ) )}{x})

\frac{d y}{d x} y = sec (x)

\frac{d}{d x} (\frac{1}{( ln ( x ) )})

\frac{d}{d x} (ln (2))

\frac{d}{d x} (ln (3))