What is the solution for -derivative of y=sin(1/x) ?

The solution for -derivative of y=sin(1/x) is y=-xsin(1/x)+\Ci(1/x)+c_{1}

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Find the Derivative - d/dx y=sin(1/x)

- \frac{d}{d x} y = sin (\frac{1}{x})

y = - x sin (\frac{1}{x}) + Ci (\frac{1}{x}) + c_{1}

Solution steps

- \frac{d y}{d x} = sin (\frac{1}{x})

Isolate

y^{'} (x) : y^{'} (x) = - sin (\frac{1}{x})

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - sin (\frac{1}{x}) d x

y = - x sin (\frac{1}{x}) + Ci (\frac{1}{x}) + c_{1}

(- 4, 4), (4, 4)

- \frac{d}{d x} (\frac{x}{5})

e^{3 x}

- \frac{d}{d x} (\frac{( sin ( x ) )}{x})

\frac{d y}{d x} y = sec (x)

What is the solution for -derivative of y=sin(1/x) ?
The solution for -derivative of y=sin(1/x) is y=-xsin(1/x)+\Ci(1/x)+c_{1}