What is the derivative of (\sqrt[3]{x}/(x-6)) ?

The derivative of (\sqrt[3]{x}/(x-6)) is (x-6-3\sqrt[3]{x}x^{2/3})/(3x^{2/3)(x-6)^2}

What is the first derivative of (\sqrt[3]{x}/(x-6)) ?

The first derivative of (\sqrt[3]{x}/(x-6)) is (x-6-3\sqrt[3]{x}x^{2/3})/(3x^{2/3)(x-6)^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

Solution steps

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

\frac{d}{d x} (x - 6) = 1

Simplify

\frac{d}{d x} (- 4 + e^{\frac{1}{2 - x}})

20 - (e^{x})^{2}, (e^{x})^{2}, [0, 0.5 ln (10)]

\frac{\partial}{\partial x} (ln (x^{2} + 9 y^{2} + 6))

\int_{0}^{1} 24 \frac{e ^{\frac{1}{x}}}{x ^{3}} d x

x \to 0 lim (e^{\frac{- 1}{x}})

What is the derivative of (\sqrt[3]{x}/(x-6)) ?
The derivative of (\sqrt[3]{x}/(x-6)) is (x-6-3\sqrt[3]{x}x^{2/3})/(3x^{2/3)(x-6)^2}
What is the first derivative of (\sqrt[3]{x}/(x-6)) ?
The first derivative of (\sqrt[3]{x}/(x-6)) is (x-6-3\sqrt[3]{x}x^{2/3})/(3x^{2/3)(x-6)^2}