What is the derivative of 8x^2cos(xcot(x)) ?

The derivative of 8x^2cos(xcot(x)) is 8(2xcos(x)cot(x)+(-cos(x)-cot(x)csc(x))x^2)

What is the first derivative of 8x^2cos(xcot(x)) ?

The first derivative of 8x^2cos(xcot(x)) is 8(2xcos(x)cot(x)+(-cos(x)-cot(x)csc(x))x^2)

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\frac{d}{d x} (8 x^{2} cos (x) cot (x))

8 (2 x cos (x) cot (x) + (- cos (x) - cot (x) csc (x)) x^{2})

Solution steps

\frac{d}{d x} (8 x^{2} cos (x) cot (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (x^{2} cos (x) cot (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = cos (x) cot (x)

= 8 (\frac{d}{d x} (x^{2}) cos (x) cot (x) + \frac{d}{d x} (cos (x) cot (x)) x^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (cos (x) cot (x)) = - cos (x) - cot (x) csc (x)

= 8 (2 x cos (x) cot (x) + (- cos (x) - cot (x) csc (x)) x^{2})

x \cdot e^{- x + 1}

(4, - 4), (8, - 10)

\int \frac{3 + x}{3 - x} d x

x^{^{''}} + x^{^{'}} + 3 x = 0

\int \frac{8 x ^{3}}{x - 4} d x

What is the derivative of 8x^2cos(xcot(x)) ?
The derivative of 8x^2cos(xcot(x)) is 8(2xcos(x)cot(x)+(-cos(x)-cot(x)csc(x))x^2)
What is the first derivative of 8x^2cos(xcot(x)) ?
The first derivative of 8x^2cos(xcot(x)) is 8(2xcos(x)cot(x)+(-cos(x)-cot(x)csc(x))x^2)