What is (\partial)/(\partial y)(y/((x+y+z))) ?

The answer to (\partial)/(\partial y)(y/((x+y+z))) is (x+z)/((x+y+z)^2)

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(\partial)/(\partial y)(y/((x+y+z)))

\frac{\partial}{\partial y} (\frac{y}{( x + y + z )})

\frac{x + z}{( x + y + z ) ^{2}}

Solution steps

\frac{\partial}{\partial y} (\frac{y}{( x + y + z )})

Treat

x, z

as constants

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{\partial}{\partial y} ( y ) ( x + y + z ) - \frac{\partial}{\partial y} ( x + y + z ) y}{( x + y + z ) ^{2}}

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (x + y + z) = 1

= \frac{1 \cdot ( x + y + z ) - 1 \cdot y}{( x + y + z ) ^{2}}

1 \cdot (x + y + z) - 1 \cdot y = x + z

= \frac{x + z}{( x + y + z ) ^{2}}

\int_{- 2}^{3} \frac{31}{x ^{4}} d x

\frac{d}{d x} (10)

2 e^{3 x} \frac{d y}{d x} = - \frac{6 x}{y ^{2}}

4 x, 4, \frac{4}{x}, 0

\int \frac{1}{4 + x - x ^{2}} d x

What is (\partial)/(\partial y)(y/((x+y+z))) ?
The answer to (\partial)/(\partial y)(y/((x+y+z))) is (x+z)/((x+y+z)^2)