What is the derivative of (3x^5(6x^4+x)^4) ?

The derivative of (3x^5(6x^4+x)^4) is 3(5x^4(6x^4+x)^4+4(6x^4+x)^3(24x^3+1)x^5)

What is the first derivative of (3x^5(6x^4+x)^4) ?

The first derivative of (3x^5(6x^4+x)^4) is 3(5x^4(6x^4+x)^4+4(6x^4+x)^3(24x^3+1)x^5)

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\frac{d}{d x} ((3 x^{5}) (6 x^{4} + x)^{4})

3 (5 x^{4} (6 x^{4} + x)^{4} + 4 (6 x^{4} + x)^{3} (24 x^{3} + 1) x^{5})

Solution steps

\frac{d}{d x} ((3 x^{5}) (6 x^{4} + x)^{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x^{5} (6 x^{4} + x)^{4})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{5}, g = (6 x^{4} + x)^{4}

= 3 (\frac{d}{d x} (x^{5}) (6 x^{4} + x)^{4} + \frac{d}{d x} ((6 x^{4} + x)^{4}) x^{5})

\frac{d}{d x} (x^{5}) = 5 x^{4}

\frac{d}{d x} ((6 x^{4} + x)^{4}) = 4 (6 x^{4} + x)^{3} (24 x^{3} + 1)

= 3 (5 x^{4} (6 x^{4} + x)^{4} + 4 (6 x^{4} + x)^{3} (24 x^{3} + 1) x^{5})

e^{x^{2}}

5 - x

ln (f (x))

\frac{1}{x - 1}

\int 8 t^{5} d t

What is the derivative of (3x^5(6x^4+x)^4) ?
The derivative of (3x^5(6x^4+x)^4) is 3(5x^4(6x^4+x)^4+4(6x^4+x)^3(24x^3+1)x^5)
What is the first derivative of (3x^5(6x^4+x)^4) ?
The first derivative of (3x^5(6x^4+x)^4) is 3(5x^4(6x^4+x)^4+4(6x^4+x)^3(24x^3+1)x^5)