What is the solution for sec^2(pi/4)(pi/5)= 1/4 (dx)/(dt) ?

The solution for sec^2(pi/4)(pi/5)= 1/4 (dx)/(dt) is x=(8pi)/5 t+c_{1}

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sec^2(pi/4)(pi/5)= 1/4 (dx)/(dt)

sec^{2} (\frac{π}{4}) (\frac{π}{5}) = \frac{1}{4} \frac{d x}{d t}

x = \frac{8 π}{5} t + c_{1}

Solution steps

sec^{2} (\frac{π}{4}) (\frac{π}{5}) = \frac{1}{4} \frac{d x}{d t}

Substitute

\frac{d x}{d t}

with

x^{'} (t)

sec^{2} (\frac{π}{4}) (\frac{π}{5}) = \frac{1}{4} x^{^{'}} (t)

Isolate

x^{'} (t) : x^{'} (t) = \frac{8 π}{5}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

x = \int \frac{8 π}{5} d t

\int \frac{8 π}{5} d t = \frac{8 π}{5} t + c_{1}

x = \frac{8 π}{5} t + c_{1}

x \to 6 + lim (6 - x)

\frac{\partial}{\partial x} ((x^{2} + y^{2})^{\frac{4}{5}})

4 x^{2} sin (x) tan (x)

\int_{- 1}^{1} x^{2} - x^{3} d x

\int \frac{3 x}{4 x ^{2} + 5} d x

What is the solution for sec^2(pi/4)(pi/5)= 1/4 (dx)/(dt) ?
The solution for sec^2(pi/4)(pi/5)= 1/4 (dx)/(dt) is x=(8pi)/5 t+c_{1}