What is the solution for ((2y)/x+2x)+((2ln(x)-3)dy)/(dx)=0 ?

The solution for ((2y)/x+2x)+((2ln(x)-3)dy)/(dx)=0 is y=-(x^2)/(2ln(x)-3)+(c_{1})/(2ln(x)-3)

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((2y)/x+2x)+((2ln(x)-3)dy)/(dx)=0

(\frac{2 y}{x} + 2 x) + \frac{( 2 ln ( x ) - 3 ) d y}{d x} = 0

y = - \frac{x ^{2}}{2 ln ( x ) - 3} + \frac{c _{1}}{2 ln ( x ) - 3}

Solution steps

(\frac{2 y}{x} + 2 x) + \frac{( 2 ln ( x ) - 3 ) d y}{d x} = 0

Solve linear ODE:

y = - \frac{x ^{2}}{2 ln ( x ) - 3} + \frac{c _{1}}{2 ln ( x ) - 3}

y = - \frac{x ^{2}}{2 ln ( x ) - 3} + \frac{c _{1}}{2 ln ( x ) - 3}

n = 0 \sum \infty n^{2} (\frac{1}{2})^{n}

x \to 0 lim ((\frac{1}{x})^{t a n (x)})

\frac{d}{d x} (cos (x - x^{2}) (1 - 2 x))

x \to 0 lim (x^{13 x})

x \to 0 lim (\frac{1}{x} ln (1 - 2 x))

What is the solution for ((2y)/x+2x)+((2ln(x)-3)dy)/(dx)=0 ?
The solution for ((2y)/x+2x)+((2ln(x)-3)dy)/(dx)=0 is y=-(x^2)/(2ln(x)-3)+(c_{1})/(2ln(x)-3)