What is the derivative of (80-x/4) ?

The derivative of (80-x/4) is -1/4

What is the first derivative of (80-x/4) ?

The first derivative of (80-x/4) is -1/4

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\frac{d}{d x} (\frac{80 - x}{4})

- \frac{1}{4}

Solution steps

\frac{d}{d x} (\frac{80 - x}{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4} \frac{d}{d x} (80 - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{4} (\frac{d}{d x} (80) - \frac{d x}{d x})

\frac{d}{d x} (80) = 0

\frac{d x}{d x} = 1

= \frac{1}{4} (0 - 1)

Simplify

= - \frac{1}{4}

\int \frac{7 x ^{3} - x ^{2} + 8 x + 12}{x ^{4} + 4 x ^{2}} d x

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x \to 0 - lim (\frac{x ^{2} - x}{x - 1})

\int_{0}^{2} 5 x^{9} d x

What is the derivative of (80-x/4) ?
The derivative of (80-x/4) is -1/4
What is the first derivative of (80-x/4) ?
The first derivative of (80-x/4) is -1/4