What is the derivative of-18cos(3x) ?

The derivative of-18cos(3x) is 54sin(3x)

What is the first derivative of-18cos(3x) ?

The first derivative of-18cos(3x) is 54sin(3x)

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\frac{d}{d x} (- 18 cos (3 x))

54 sin (3 x)

Solution steps

\frac{d}{d x} (- 18 cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 18 \frac{d}{d x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{d}{d x} (3 x)

= - sin (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= - 18 (- sin (3 x) \cdot 3)

Simplify

= 54 sin (3 x)

\int \frac{sin ^{5} ( θ )}{cos ( θ )} d θ

f (x) = (3 x^{3} + 3 x) (x - 3) (x + 5)

e^{x} x^{4} + 8 e^{x} x^{3} + 12 e^{x} x^{2}

\frac{d y}{d x} = 1 - y + x^{2} - y x^{2}

\int_{0}^{1} (x^{2} + 1) e^{- x} d x

What is the derivative of-18cos(3x) ?
The derivative of-18cos(3x) is 54sin(3x)
What is the first derivative of-18cos(3x) ?
The first derivative of-18cos(3x) is 54sin(3x)