What is the integral from 0 to 2 of sin(x) ?

The integral from 0 to 2 of sin(x) is -cos(2)+1

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integral from 0 to 2 of sin(x)

\int_{0}^{2} sin (x) d x

- cos (2) + 1

Decimal Notation

1.41614 \dots

Solution steps

\int_{0}^{2} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{2}

Compute the boundaries:

- cos (2) + 1

= - cos (2) + 1

\int \frac{- 5 x + 2}{( x + 1 ) ^{2}} d x

\frac{d}{d x} (cos (x - \frac{π}{6}))

y^{^{'}} = y e^{x}

y = (1 - 5 x)^{6}

y = 7 x + 1, (5, 6)

What is the integral from 0 to 2 of sin(x) ?
The integral from 0 to 2 of sin(x) is -cos(2)+1