What is the tangent of y=x^2-7x+7,(0,7) ?

The tangent of y=x^2-7x+7,(0,7) is y=-7x+7

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tangent of y=x^2-7x+7,(0,7)

tangent of

y = x^{2} - 7 x + 7, (0, 7)

y = - 7 x + 7

Solution steps

Find the slope of

y = x^{2} - 7 x + 7 : \frac{d y}{d x} = 2 x - 7

Compute the slope of

y = x^{2} - 7 x + 7

(0, 7) : m = - 7

Find the line with slope m=

- 7

and passing through

(0, 7) : y = - 7 x + 7

y = - 7 x + 7

\int \frac{1}{x} cos^{2} (x) d x

\int_{0}^{a} 7 x^{2} a^{2} - x^{2} d x

\frac{d}{d x} (4 x^{2} - 8 x)

\int \frac{x ^{2}}{( 1 + x ^{3} ) ^{1.7}} d x

(38) (3 - 4)

What is the tangent of y=x^2-7x+7,(0,7) ?
The tangent of y=x^2-7x+7,(0,7) is y=-7x+7