What is (\partial)/(\partial y)(y-x^2) ?

The answer to (\partial)/(\partial y)(y-x^2) is 1

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(\partial)/(\partial y)(y-x^2)

\frac{\partial}{\partial y} (y - x^{2})

1

Solution steps

\frac{\partial}{\partial y} (y - x^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y) - \frac{\partial}{\partial y} (x^{2})

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (x^{2}) = 0

= 1 - 0

Simplify

= 1

\int 3^{3}

\int (\frac{1}{x} - 1)^{2} d x

f (x) = cos (\frac{x + 1}{x - 1})

\frac{\partial}{\partial x} (3 x^{2} y - y^{3} + x - y)

x \to 0 lim (x^{3} cos (\frac{2}{x}))

What is (\partial)/(\partial y)(y-x^2) ?
The answer to (\partial)/(\partial y)(y-x^2) is 1