What is the integral from 3pi to 4pi of 2sin(x) ?

The integral from 3pi to 4pi of 2sin(x) is -4

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integral from 3pi to 4pi of 2sin(x)

\int_{3 π}^{4 π} 2 sin (x) d x

- 4

Solution steps

\int_{3 π}^{4 π} 2 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{3 π}^{4 π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 2 [- cos (x)]_{3 π}^{4 π}

Compute the boundaries:

- 2

= 2 (- 2)

Simplify

= - 4

\int \frac{1}{x 9 x ^{2} - 16} d x

\frac{\partial}{\partial y} (2 x^{2} + y^{2})

x^{2} \frac{d y}{d x} = x y + x^{2} e^{\frac{y}{x}}

y^{^{''}} + 6 y + 8 = 0, y (0) = 0, y^{^{'}} (0) = 12

f (x) = 4 x^{6} - 5 x^{- 5} + 3 x - \frac{6}{x ^{4}} - 5 e^{x}

What is the integral from 3pi to 4pi of 2sin(x) ?
The integral from 3pi to 4pi of 2sin(x) is -4