What is the derivative of cos(3x+2-(2x+1)^{-3}) ?

The derivative of cos(3x+2-(2x+1)^{-3}) is -3sin(3x+2)+6/((2x+1)^4)

What is the first derivative of cos(3x+2-(2x+1)^{-3}) ?

The first derivative of cos(3x+2-(2x+1)^{-3}) is -3sin(3x+2)+6/((2x+1)^4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (cos (3 x + 2) - (2 x + 1)^{- 3})

- 3 sin (3 x + 2) + \frac{6}{( 2 x + 1 ) ^{4}}

Solution steps

\frac{d}{d x} (cos (3 x + 2) - (2 x + 1)^{- 3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (cos (3 x + 2)) - \frac{d}{d x} ((2 x + 1)^{- 3})

\frac{d}{d x} (cos (3 x + 2)) = - sin (3 x + 2) \cdot 3

\frac{d}{d x} ((2 x + 1)^{- 3}) = - \frac{6}{( 2 x + 1 ) ^{4}}

= - sin (3 x + 2) \cdot 3 - (- \frac{6}{( 2 x + 1 ) ^{4}})

Simplify

= - 3 sin (3 x + 2) + \frac{6}{( 2 x + 1 ) ^{4}}

\int \frac{sin ( y )}{x} d x

f (x) = \frac{r}{r ^{2} + 5}

\frac{d}{d x} (g (x) (x^{3}))

\frac{\partial}{\partial x} (y x^{2} + 6 x^{3} + x y)

What is the derivative of cos(3x+2-(2x+1)^{-3}) ?
The derivative of cos(3x+2-(2x+1)^{-3}) is -3sin(3x+2)+6/((2x+1)^4)
What is the first derivative of cos(3x+2-(2x+1)^{-3}) ?
The first derivative of cos(3x+2-(2x+1)^{-3}) is -3sin(3x+2)+6/((2x+1)^4)