What is (\partial)/(\partial x)(x^2+y^2+x^2y+4) ?

The answer to (\partial)/(\partial x)(x^2+y^2+x^2y+4) is 2xy+2x

Popular >

(\partial)/(\partial x)(x^2+y^2+x^2y+4)

\frac{\partial}{\partial x} (x^{2} + y^{2} + x^{2} y + 4)

2 x y + 2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} + y^{2} + x^{2} y + 4)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (y^{2}) + \frac{\partial}{\partial x} (x^{2} y) + \frac{\partial}{\partial x} (4)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (x^{2} y) = 2 y x

\frac{\partial}{\partial x} (4) = 0

= 2 x + 0 + 2 y x + 0

Simplify

= 2 x y + 2 x

\frac{d}{d x} (3 x^{2} + 5 x + 8)

\int cos (6 t) d t

4 2 x, 2 x^{2}, - 4 x + 6

(t + 2) y^{'} + y = \frac{1}{t - 1}

\frac{\partial}{\partial l} (2 π \frac{l}{g})

What is (\partial)/(\partial x)(x^2+y^2+x^2y+4) ?
The answer to (\partial)/(\partial x)(x^2+y^2+x^2y+4) is 2xy+2x