What is the solution for 16y^{''}-pi^2y=0 ?

The solution for 16y^{''}-pi^2y=0 is y=c_{1}e^{(pit)/4}+c_{2}e^{-(pit)/4}

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16y^{''}-pi^2y=0

16 y^{^{''}} - π^{2} y = 0

y = c_{1} e^{\frac{π t}{4}} + c_{2} e^{- \frac{π t}{4}}

Solution steps

16 y^{''} (t) - π^{2} y = 0

Solve linear ODE:

y = c_{1} e^{\frac{π t}{4}} + c_{2} e^{- \frac{π t}{4}}

y = c_{1} e^{\frac{π t}{4}} + c_{2} e^{- \frac{π t}{4}}

\int x^{2} x^{3} + 15 d x

n = 1 \sum \infty e^{(- n^{2})}

x \to - 5 lim (- \frac{9}{x + 5})

\frac{d}{d x} (ln (\frac{x ^{2} - 1}{x ^{2} + 1}))

\int (5 + x) d x

What is the solution for 16y^{''}-pi^2y=0 ?
The solution for 16y^{''}-pi^2y=0 is y=c_{1}e^{(pit)/4}+c_{2}e^{-(pit)/4}