What is the solution for (dy)/(dx)=((2xy+2x))/(x^2+1) ?

The solution for (dy)/(dx)=((2xy+2x))/(x^2+1) is y=e^{c_{1}}x^2+e^{c_{1}}-1

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(dy)/(dx)=((2xy+2x))/(x^2+1)

\frac{d y}{d x} = \frac{( 2 x y + 2 x )}{x ^{2} + 1}

y = e^{c_{1}} x^{2} + e^{c_{1}} - 1

Solution steps

\frac{d y}{d x} = \frac{( 2 x y + 2 x )}{x ^{2} + 1}

Solve separable ODE:

y = e^{c_{1}} x^{2} + e^{c_{1}} - 1

y = e^{c_{1}} x^{2} + e^{c_{1}} - 1

x \to 3 lim (4 x - a + b)

\int_{0}^{1} 7 e^{x} - 7 x e^{x^{2}} d x

\frac{d}{d x} (sin (\frac{π}{2} x))

\int_{0}^{6} \frac{7 t}{( t - 7 ) ^{2}} d t

\frac{e ^{- 4 s}}{s ^{2}}

What is the solution for (dy)/(dx)=((2xy+2x))/(x^2+1) ?
The solution for (dy)/(dx)=((2xy+2x))/(x^2+1) is y=e^{c_{1}}x^2+e^{c_{1}}-1