What is the derivative of f(x)=\sqrt[7]{x^6}-x^pi ?

The derivative of f(x)=\sqrt[7]{x^6}-x^pi is (6x^5)/(7(x^6)^{6/7)}-pix^{pi-1}

What is the first derivative of f(x)=\sqrt[7]{x^6}-x^pi ?

The first derivative of f(x)=\sqrt[7]{x^6}-x^pi is (6x^5)/(7(x^6)^{6/7)}-pix^{pi-1}

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derivative of

\frac{6 x ^{5}}{7 ( x ^{6} ) ^{\frac{6}{7}}} - π x^{π - 1}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (x^{π}) = π x^{π - 1}

= \frac{6 x ^{5}}{7 ( x ^{6} ) ^{\frac{6}{7}}} - π x^{π - 1}

\frac{d y}{d x}, x^{(\frac{2}{3})} + y^{(\frac{2}{3})} = 10

f (t) = 8 cos (t)

\frac{\partial}{\partial x} (\frac{2 x}{x + 1})

Y (θ) = cot^{2} (cos (θ))

f (t) = 6 t - 5 t^{2}

What is the derivative of f(x)=\sqrt[7]{x^6}-x^pi ?
The derivative of f(x)=\sqrt[7]{x^6}-x^pi is (6x^5)/(7(x^6)^{6/7)}-pix^{pi-1}
What is the first derivative of f(x)=\sqrt[7]{x^6}-x^pi ?
The first derivative of f(x)=\sqrt[7]{x^6}-x^pi is (6x^5)/(7(x^6)^{6/7)}-pix^{pi-1}