What is the derivative of (x^3+6e^x) ?

The derivative of (x^3+6e^x) is 3x^2e^x+e^x(x^3+6)

What is the first derivative of (x^3+6e^x) ?

The first derivative of (x^3+6e^x) is 3x^2e^x+e^x(x^3+6)

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Popular >

\frac{d}{d x} ((x^{3} + 6) e^{x})

3 x^{2} e^{x} + e^{x} (x^{3} + 6)

Solution steps

\frac{d}{d x} ((x^{3} + 6) e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{3} + 6, g = e^{x}

= \frac{d}{d x} (x^{3} + 6) e^{x} + \frac{d}{d x} (e^{x}) (x^{3} + 6)

\frac{d}{d x} (x^{3} + 6) = 3 x^{2}

\frac{d}{d x} (e^{x}) = e^{x}

= 3 x^{2} e^{x} + e^{x} (x^{3} + 6)

\frac{d}{d x} (sinh (0))

f (x) = x^{2}, at x = 3, x = 7

\int_{1}^{5} \frac{4}{x ^{2} + 4 x + 4} d x

\frac{d v}{d t} = \frac{1}{t ^{2}}

x \to 8 - lim (\frac{x ^{8}}{x - 8})

What is the derivative of (x^3+6e^x) ?
The derivative of (x^3+6e^x) is 3x^2e^x+e^x(x^3+6)
What is the first derivative of (x^3+6e^x) ?
The first derivative of (x^3+6e^x) is 3x^2e^x+e^x(x^3+6)