What is the tangent of f(x)=-5x^2+6,\at x=5 ?

The tangent of f(x)=-5x^2+6,\at x=5 is y=-50x+131

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tangent of f(x)=-5x^2+6,\at x=5

tangent of

f (x) = - 5 x^{2} + 6, at x = 5

y = - 50 x + 131

Solution steps

Find the tangent point:

(5, - 119)

Find the slope of

f (x) = - 5 x^{2} + 6 : \frac{df ( x )}{d x} = - 10 x

Compute the slope of

f (x) = - 5 x^{2} + 6

x = 5 : m = - 50

Find the line with slope m=

- 50

and passing through

(5, - 119) : y = - 50 x + 131

y = - 50 x + 131

x \to - 3 lim (4 x + 28 - 4)

\frac{d}{d x} (\frac{7 x}{2 x ^{3}})

\frac{d}{d x} ((x^{3} + 2)^{2} (x^{5} + 4)^{4})

\int (2 x + 5)^{2} d x

What is the tangent of f(x)=-5x^2+6,\at x=5 ?
The tangent of f(x)=-5x^2+6,\at x=5 is y=-50x+131