What is the integral of (tan(x))^3(sec(x))^2 ?

The integral of (tan(x))^3(sec(x))^2 is (tan^4(x))/4+C

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integral of (tan(x))^3(sec(x))^2

\int (tan (x))^{3} (sec (x))^{2} d x

\frac{tan ^{4} ( x )}{4} + C

Solution steps

\int (tan (x))^{3} (sec (x))^{2} d x

Simplify

= \int tan^{3} (x) sec^{2} (x) d x

Rewrite using trig identities

= \int (1 + tan^{2} (x)) tan^{3} (x) d x

Apply u-substitution

: \int u^{3} d u

= \int u^{3} d u

Apply the Power Rule

: \frac{u ^{4}}{4}

= \frac{u ^{4}}{4}

Substitute back

u = tan (x)

= \frac{tan ^{4} ( x )}{4}

Add a constant to the solution

= \frac{tan ^{4} ( x )}{4} + C

\frac{1}{x ^{4}}

\frac{d}{d x} (x^{4} + 5 x^{- 1})

\frac{\partial}{\partial y} (sec^{2} (y t))

\frac{d}{d x} (e^{2 s i n (3 x)})

\frac{d}{d x} (\frac{x + 1}{x ^{2} - 5})

What is the integral of (tan(x))^3(sec(x))^2 ?
The integral of (tan(x))^3(sec(x))^2 is (tan^4(x))/4+C