What is the integral of-cos(u) ?

The integral of-cos(u) is -sin(u)+C

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integral of-cos(u)

\int - cos (u) d u

- sin (u) + C

Solution steps

\int - cos (u) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= - sin (u)

Add a constant to the solution

= - sin (u) + C

\frac{\partial}{\partial x} (ln (5 x^{2} + y^{2} + 9))

\frac{d ^{2} y}{d x ^{2}} - 5 \frac{d y}{d x} + 6 y = 0

f (x) = \frac{22}{( 1 - x ) ^{3}}

y = x^{2} - 2 x, (3, 3)

\frac{d y}{d x} = \frac{x ^{2}}{9} + \frac{7}{9}