What is the tangent of y= 6/(sin(x)+cos(x)),(0,6) ?

The tangent of y= 6/(sin(x)+cos(x)),(0,6) is y=-6x+6

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tangent of y= 6/(sin(x)+cos(x)),(0,6)

tangent of

y = \frac{6}{sin ( x ) + cos ( x )}, (0, 6)

y = - 6 x + 6

Solution steps

Find the slope of

y = \frac{6}{sin ( x ) + cos ( x )} : \frac{d y}{d x} = - \frac{6 ( cos ( x ) - sin ( x ) )}{1 + sin ( 2 x )}

Compute the slope of

y = \frac{6}{sin ( x ) + cos ( x )}

(0, 6) : m = - 6

Find the line with slope m=

- 6

and passing through

(0, 6) : y = - 6 x + 6

y = - 6 x + 6

x \to 1 + lim (\frac{4}{2 x - 2})

\frac{\partial}{\partial x} (x^{2} - 2 x - x y)

x \to \infty lim (\frac{ln ( x ^{5} )}{13 x})

\frac{\partial}{\partial x} (e^{- \frac{x}{y}})

\int π (2 x)^{2} d x

What is the tangent of y= 6/(sin(x)+cos(x)),(0,6) ?
The tangent of y= 6/(sin(x)+cos(x)),(0,6) is y=-6x+6