What is the solution for 9x^2y^2+x^{3/2}y^'=y^2 ?

The solution for 9x^2y^2+x^{3/2}y^'=y^2 is y=-(x^{1/2})/(-2-6x^2+c_{1)x^{1/2}}

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9x^2y^2+x^{3/2}y^'=y^2

9 x^{2} y^{2} + x^{\frac{3}{2}} y^{^{'}} = y^{2}

y = - \frac{x ^{\frac{1}{2}}}{- 2 - 6 x ^{2} + c _{1} x ^{\frac{1}{2}}}

Solution steps

9 x^{2} y^{2} + x^{\frac{3}{2}} y^{'} (x) = y^{2}

Solve separable ODE:

y = - \frac{x ^{\frac{1}{2}}}{- 2 - 6 x ^{2} + c _{1} x ^{\frac{1}{2}}}

y = - \frac{x ^{\frac{1}{2}}}{- 2 - 6 x ^{2} + c _{1} x ^{\frac{1}{2}}}

(x^{2} - 18) (2 x + 3)

\int x + \frac{1}{x ^{2}} d x

\frac{\partial}{\partial x} (x y - 1)

\frac{\partial}{\partial y} ((x^{2} - 1) (y + 2))

f (x) = \frac{3}{x ^{2}}, at x = 1

What is the solution for 9x^2y^2+x^{3/2}y^'=y^2 ?
The solution for 9x^2y^2+x^{3/2}y^'=y^2 is y=-(x^{1/2})/(-2-6x^2+c_{1)x^{1/2}}