What is the sum from n=0 to infinity of (1^n)/(4^n) ?

The sum from n=0 to infinity of (1^n)/(4^n) is converges

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sum from n=0 to infinity of (1^n)/(4^n)

n = 0 \sum \infty \frac{1 ^{n}}{4 ^{n}}

converges

Solution steps

n = 0 \sum \infty \frac{1 ^{n}}{4 ^{n}}

Apply Series Ratio Test:

converges

= converges

(3 x - 2)^{^{'}}

x \to 3 + lim (\frac{5 x}{x - 3})

f (x) = \frac{6}{3 x + 1}, at x = - 1

y = \frac{0.9 e ^{x}}{tan ( x )}

f (x) = - 4 sin (2 x) + 3 cos (3 x)

What is the sum from n=0 to infinity of (1^n)/(4^n) ?
The sum from n=0 to infinity of (1^n)/(4^n) is converges