What is the sum from n=1 to infinity of (n+2)/(n+1) ?

The sum from n=1 to infinity of (n+2)/(n+1) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of (n+2)/(n+1)

n = 1 \sum \infty \frac{n + 2}{n + 1}

diverges

Solution steps

n = 1 \sum \infty \frac{n + 2}{n + 1}

Apply Series Divergence Test:

diverges

= diverges

\int ((1 - cos^{3} (x)) sin (x)) d x

\int (sin^{9} (x)) cos (x) d x

x \to 0 lim (\frac{sin ( 6 x )}{x})

\int λ e^{- λ x} d x

\int 2 sin (2 t) d t

What is the sum from n=1 to infinity of (n+2)/(n+1) ?
The sum from n=1 to infinity of (n+2)/(n+1) is diverges