What is the derivative of 1/(4x^4) ?

The derivative of 1/(4x^4) is -1/(x^5)

What is the first derivative of 1/(4x^4) ?

The first derivative of 1/(4x^4) is -1/(x^5)

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derivative of

\frac{1}{4 x ^{4}}

- \frac{1}{x ^{5}}

Solution steps

\frac{d}{d x} (\frac{1}{4 x ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4} \frac{d}{d x} (\frac{1}{x ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{4} \frac{d}{d x} (x^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{4} (- 4 x^{- 4 - 1})

Simplify

\frac{1}{4} (- 4 x^{- 4 - 1}) : - \frac{1}{x ^{5}}

= - \frac{1}{x ^{5}}

\frac{d y}{d x} = 4 (x^{2} + 1), x (\frac{π}{4}) = 1

\int (8 x^{3} + \frac{1}{x ^{2}}) d x

y = 2^{- x}, (- 1, 2)

\frac{d}{d x} (1 - 4 cos (x))

\int_{- 2}^{2} \frac{1}{x ^{2} - 9} d x

What is the derivative of 1/(4x^4) ?
The derivative of 1/(4x^4) is -1/(x^5)
What is the first derivative of 1/(4x^4) ?
The first derivative of 1/(4x^4) is -1/(x^5)