What is the derivative of e^{3x}-1 ?

The derivative of e^{3x}-1 is 3e^{3x}

What is the first derivative of e^{3x}-1 ?

The first derivative of e^{3x}-1 is 3e^{3x}

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\frac{d}{d x} (e^{3 x} - 1)

3 e^{3 x}

Solution steps

\frac{d}{d x} (e^{3 x} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{3 x}) - \frac{d}{d x} (1)

\frac{d}{d x} (e^{3 x}) = e^{3 x} \cdot 3

\frac{d}{d x} (1) = 0

= e^{3 x} \cdot 3 - 0

Simplify

= 3 e^{3 x}

\int_{2}^{4} \frac{x + y}{55} d y

\int \frac{x ( x - 8 )}{( x - 4 ) ^{3}} d x

2 (2 x^{2} + y^{2}) d x - x y d y = 0

f (x) = \frac{x - 5}{x + 3}

f (x) = 5 x^{2} - 2 x + 4

What is the derivative of e^{3x}-1 ?
The derivative of e^{3x}-1 is 3e^{3x}
What is the first derivative of e^{3x}-1 ?
The first derivative of e^{3x}-1 is 3e^{3x}